Wade Set To Become Free Agent, Leaves Heat
The most accomplished player of Miami Heat’s history is about to leave the team. Dwyane Wade has opted out of the final year of his player’s contract to become a free agent. Earlier, rumors were getting louder that All-star guard Wade would become this season’s first fascinating free agent. The Los Angeles Lakers are eying to rope in Wade as a partner of Kobe Bryant, according to sources close to the league. Goran Dragic of Miami Heats has already headed to free agency.
Wade is ready to face the challenge of the open market to find his worth. From Wednesday, he becomes a free agent by passing a $16.1 million final year player’s option with Miami. His decision was announced on Monday afternoon in a 61-word press release, as both Wade and his agent Henry Thomas didn’t respond to requests of commenting on the issue.
Wade had been a All-star in 11 of 12 seasons he spent at Miami. He represented all three of Miami’s NBA sides. He is the all-time leader in many categories such as games, points, assists and steals.
“We want Dwyane back,” Heat President Pat Riley said last week. “There’s no doubt about that.”
It’s unlikely to happen, though. Wade isn’t satisfied with the current deal, as he’s sacrificed $27 million in his stint at Miami and wants to be compensated duly.
“Obviously, our team went through a lot of bizarre stuff throughout this year but I thought individually, what I was able to do in 30, 31 minutes, I thought I was as efficient as I could be,” Wade said in an interview with The Associated Press when the season ended. “I always think I can do better, but what I was able to accomplish … I thought was pretty good individually.”
Loul Deng is staying at Miami.